# C break and continue

C break and continue: we learned about loops in previous tutorials. In this tutorial, we will learn to use the break and continue statements with the help of examples.

C break
The break statement ends the loop immediately when it is encountered. Its syntax is:

`break;`

The break statement is almost always used with the if..else statement inside the loop.

Contents

## Example 1: break statement

```// Program to calculate the sum of a maximum of 10 numbers
// If a negative number is entered, the loop terminates

# include <stdio.h>
int main()
{
int i;
double number, sum = 0.0;

for(i=1; i <= 10; ++i)
{
printf("Enter a n%d: ",i);
scanf("%lf",&number);

// If the user enters a negative number, the loop ends
if(number < 0.0)
{
break;
}

sum += number; // sum = sum + number;
}

printf("Sum = %.2lf",sum);

return 0;
}```

Output

```Enter a n1: 2.4
Enter a n2: 4.5
Enter a n3: 3.4
Enter a n4: -3
Sum = 10.30```

This program calculates the sum of a limit of 10 numbers. Why a limit of 10 numbers? This is supposing that the client enters a negative number, the break statement is executed. This will end the for loop, and the sum is shown.

In C, the break is also used with the switch statement. This will be discussed in the next tutorial.

## C continue

The continue statement skips the current iteration of the loop and continues with the next iteration. Its syntax is:

`continue;`

The continue statement is almost always used with the if…else statement.

## Example 2: continue statement

```// Program to calculate the sum of a maximum of 10 numbers
// Negative numbers are skipped from the calculation

# include <stdio.h>
int main()
{
int i;
double number, sum = 0.0;

for(i=1; i <= 10; ++i)
{
printf("Enter a n%d: ",i);
scanf("%lf",&number);

if(number < 0.0)
{
continue;
}

sum += number; // sum = sum + number;
}

printf("Sum = %.2lf",sum);

return 0;
}```

Output

```Enter a n1: 1.1
Enter a n2: 2.2
Enter a n3: 5.5
Enter a n4: 4.4
Enter a n5: -3.4
Enter a n6: -45.5
Enter a n7: 34.5
Enter a n8: -4.2
Enter a n9: -1000
Enter a n10: 12
Sum = 59.70```

In this program, when the client enters a positive number, the sum is calculated using sum += number; statement.

When the client enters a negative number, the continue with proclamation is executed and it avoids the negative number from the calculation.

Please feel free to give your comment if you face any difficulty here.